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| 1. |
Find the sum of all 3 digit numbers which leave remainder 3 when divided by 5. |
| Answer» Three digit numbers which leave the remainder 3 when divided by 5 are 103, 108, 113,......., 998.103, 108, 113,......, 998 is an A.PFirst term of the A.P,\xa0a\xa0= 103Common different of the A.P,\xa0d\xa0= 5Let 998 be the\xa0nth\xa0term of the A.P.an\xa0=\xa0a\xa0+ (n\xa0– 1)\xa0d∴ 103 + (n\xa0– 1) × 5 = 998⇒ 5 (n\xa0– 1) = 998 – 103 = 895 ⇒ (n\xa0– 1) = 179⇒ n\xa0= 180Sum of all three digit numbers which leaves remainder 3 when divided by 5was this answer useful??????\xa0 | |