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| 1. |
Find the sum of all the 11 terms of an AP whose middle most term is 30 |
| Answer» given n =11middle term = (a1 + a11)/2 = 30a1 + a11 = 60 .......... iSn = n/2(a1 + a11) ......... ii = 11/2 (60) ... from i = 11 x 30 = 330 | |