1.

Find the sum of all. The 11term of an ap whose middle most term.is 30

Answer» We can say that 30 is the Median of 11 terms.thereforewe knowM = (n + 1)/2 th observation for n = oddTherefore the 6th term of this AP is 30Therefore A6 = 30a + 5d = 30therefore we need to find S11Therefore S11 = n/2(2a + (n-1)d)=11/2(2a + 10d)=11/2(2(a + 5d)replacing value=11/2(2(30))=11 * 30=330therefore Answer is 330
330


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