Find the sum of first 40 positive integers divisible by 6

1.	Find the sum of first 40 positive integers divisible by 6
Answer» Acc.to que.\xa040 positive integers which are divisible by 6 is can be written in the form of A.p\xa06+12+18+..........+240a= 6 , d = a2 - a1 = 12 -6 =6n= 40 and an or nth terms = 240Therefore\xa0\xa0Sn = n/2 ×(a +an)= 4o/2 ×(6+240)=20×246=4920Hence sum of 40 positive integers which r divisible by 6 is 4920\xa0

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