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| 1. |
Find the sum of "n" term of the series :[4 - 1/n] + [4 - 2/n] + [4 - 3/n] + ............... |
| Answer» this is an APa=4-1/n ,d=-1/nso Sn=n/2{ 2(4-1/n) +(n-1)(-1/n)}=n/2 x (8-2/n-1+1/n)=n/2 x(7-1/n)=n/2 x (7n-1)/n=(7n-1)/2 | |