Find the sum of n terms of the sequence {an}, where n is equal to 5 - 6n and n is a natural number

Find the sum of n terms of the sequence {an}, where n is equal to 5 -

1.	Find the sum of n terms of the sequence {an}, where n is equal to 5 - 6n and n is a natural number
Answer» Answer shi nhi hai kya Unable to understand ?? It\'s my pleasure ?? Thanks an = 5 - 6n1 ) a1 = 5 - 6= -12 ) a2 = 5 - 12 = -73 ) a3 = 5 - 18 = -13d = a2 - a1d = -7 - ( -1 ) = -7 +1 = -6now ,a = - 1 , d = -6sum of n terms = n/2 [ 2a + ( n - 1 ) d]Sn = n/2[ 2×(-1 ) + ( n -1 )(-6) ]Sn = n/2 [ -2 -6n + 6 ]= n/2 [4 - 6n ]= n(2-3n )(I hope this helps you.)?