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| 1. |
Find the sum of the 40 positive integer divisible by 6 |
| Answer» We know that the first 40 positive integers divisible by 6 are 6,12,18,....This is an AP with a = 6 and d = 6S40 = n/2 [2a + (n - 1)d]S40 = 20[2(6) +(40-1)6]= 20[12+234]= 4920 | |