Find the sum of the following Aps -37,-33,-29,...,to 12 terms.

1.	Find the sum of the following Aps -37,-33,-29,...,to 12 terms.
Answer» Here, {tex}a=-37,\\ d=-33-(-37)=-33+37=4\\ and\\ n=12{/tex}Now we know that ,\xa0Sn={tex}\\frac{n}{2}{/tex}[2a+(n-1)d]Therefore, S12=\xa0{tex}\\frac{{12}}{2}{/tex}[2{tex}\\times{/tex}{tex}(-37)+(12-1)4]{/tex}= {tex}6[-74+44]{/tex}= 6{tex}\\times{/tex}(-30)= -180Therefore, sum of given A.P is -180.

Discussion