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Find the two numbers whose sum is 27 and product is182?

Answer» 13 &14
13 and 14
13 and 14
13 and 14
Let the first number be\xa0x\xa0and the second number is 27 -\xa0x.Therefore, their product =\xa0x\xa0(27 -\xa0x)It is given that the product of these numbers is 182.Therefore,\xa0x(27 -\xa0x) = 182⇒\xa0x2\xa0– 27x\xa0+ 182 = 0⇒\xa0x2\xa0– 13x\xa0- 14x\xa0+ 182 = 0⇒\xa0x(x\xa0- 13) -14(x\xa0- 13) = 0⇒ (x\xa0- 13)(x\xa0-14) = 0Either\xa0x\xa0= -13\xa0= 0 or\xa0x\xa0- 14 = 0⇒\xa0x\xa0= 13 or\xa0x\xa0= 14If first number = 13, thenOther number = 27 - 13 = 14If first number = 14, thenOther number = 27 - 14 = 13Therefore, the numbers are 13 and 14.


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