Find the value of (-1)^n+(-1)^2n+(-1)^2n+1+(-1)^4n+2,where n is any positive odd integer

Find the value of (-1)^n+(-1)^2n+(-1)^2n+1+(-1)^4n+2,where n is any po

1.	Find the value of (-1)^n+(-1)^2n+(-1)^2n+1+(-1)^4n+2,where n is any positive odd integer
Answer» Since, n is an odd integer, (-1)^n = -1(-1)^ 2n = +1(-1)^2n+1 = -1(-1)^4n+2 = +1So, -1+(+1)+(-1)+(+1)= 0 Whenever power of ( -1) is odd then answer is -1 , it doesn\'t matter how big power is , so answer is ............( -1)+(-1)+(-1)+(-1) = -4