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| 1. |
Find the value of 10 square 10 - cot square 80 |
| Answer» Given, tan210°-cot280°=\xa0tan2(90° - 80°) - cot280°{tex}[\\because tan(90^o-\\theta)=cot\\theta]{/tex}= cot280° - cot280°= 0 | |