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Find the value of(3tan 41/cot 49)241 |
| Answer» Full question:\xa0Find the value of: (3 tan 41/cot 49)^2 - (sin35sec55/tan10tan20tan60tan70tan80)^2Answer:26/3Step-by-step explanation:Given find the value of:(3 tan 41/cot 49)^2 - (sin35 sec55 / tan10 tan20 tan60 tan70 tan80)^2(3 tan 41 / cot (90 - 41) - sin 35 sec(90 - 35) / tan 10. tan 20. tan 60 . tan(90 - 20) tan(90 - 10)(3 tan 41 / tan 41)^2 - (sin 35 sec(90 - 35) / tan 10 tan 20 tan 60 tan(90 - 20)tan(90 - 10))^2(3 x 1)^2 - (sin 35 cosec 35 / tan 10. cot 10. tan 20. cot 20. tan 60)^29 - (1 / 1 x 1 x √3)^2 (because cosec 35 = 1/sin35)9 - 1 / 327 - 1 / 3\xa026 / 3 | |