Find the value of \'a\' so that the point (3,9) lies on the line represented by 2x-2y=5

Find the value of \'a\' so that the point (3,9) lies on the line repre

1.	Find the value of \'a\' so that the point (3,9) lies on the line represented by 2x-2y=5
Answer» Since the point (3, a) lies on the line 2x - 3y = 5, we have2\xa0{tex}\\times{/tex}\xa03 - 3\xa0{tex}\\times{/tex}\xa0a = 5{tex}\\Rightarrow{/tex}\xa06 - 3a = 5{tex}\\Rightarrow{/tex}\xa03a = 1{tex}\\Rightarrow{/tex}\xa0{tex}a = \\frac { 1 } { 3 }{/tex}