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| 1. |
Find the value of a when the distance between the points (3 ,a)and (4,1) is root10 |
| Answer» DISTANCE= root (3-4)2 + (a-1)2 = root 1+a2+1-2a=root 10 squaring both sides\xa0a2-2a+2=10a2-2a-8=0a2-4a+2a-8=0a(a-4) + 2(a-4)=0a=4 or - 2 | |