1.

Find the value of \(\begin{vmatrix}sin\,A &-sin\,B \\[0.3em]cos\,A & cos\,B \\[0.3em]\end{vmatrix}\)  where A = 53°, B = 37°.

Answer»

Let \(\Delta=\begin{vmatrix}sin\,A &-sin\,B \\[0.3em]cos\,A & cos\,B \\[0.3em]\end{vmatrix}\)

Δ = sin A cos B + sin B cos A

⇒ Δ =  sin (A + B)

Δ =  sin (53 + 37)

= sin 90°

= 1.



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