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Find the value of \(\begin{vmatrix}sin\,A &-sin\,B \\[0.3em]cos\,A & cos\,B \\[0.3em]\end{vmatrix}\) where A = 53°, B = 37°. |
Answer» Let \(\Delta=\begin{vmatrix}sin\,A &-sin\,B \\[0.3em]cos\,A & cos\,B \\[0.3em]\end{vmatrix}\) Δ = sin A cos B + sin B cos A ⇒ Δ = sin (A + B) Δ = sin (53 + 37) = sin 90° = 1. |
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