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| 1. |
Find the value of cot 10 cot 30 cot 30? |
| Answer» = cot 10° cot 30° cot 80°= cot (90° - 80°) cot 30° cot 80°{tex}[\\because cot(90^o-\\theta)=tan\\theta]{/tex}{tex}=tan80^o. cot30^o{/tex}.{tex}\\frac { 1 } { \\tan 80 ^ { \\circ } }{/tex}{tex}[\\because cot\\theta=\\frac{1}{tan\\theta}]{/tex}{tex}=cot30^o{/tex}\xa0{tex}=\\sqrt{3}{/tex}Therefore,\xa0{tex}cot10^o cot30^o cot80^o=\\sqrt{3}{/tex}{tex}{/tex} | |