1.

Find the value of : (i) antilog 0.654 (ii) antilog 1.204 (iii) antilog `bar(1).3612` (iv) antilog `bar(3).4568`

Answer» We have
(i) antilog (0.654) = 4.508
(ii) antilog (1.204) = 16.00
(iii) antilog `(bar(1).3612) = 0.2297`
(iv) antilog `(bar(3).4568) = 0.002863`


Discussion

No Comment Found