Find the value of k,(-4) is a zero of the polynomial x^2-x-(2k+2)

1.	Find the value of k,(-4) is a zero of the polynomial x^2-x-(2k+2)
Answer» Given that, -4 is a zero of the polynomial f(x) =\xa0x2 - x - (2k + 2), so, we havef(-4) = 0{tex}\\Rightarrow{/tex}\xa0(-4)2\xa0- (-4) - 2k - 2 = 0{tex}\\Rightarrow{/tex}\xa016 + 4 - 2k - 2 = 0{tex}\\Rightarrow{/tex}\xa018 - 2k = 0{tex}\\Rightarrow{/tex}\xa02k = 18{tex}\\Rightarrow{/tex} k = 9.

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