Find the value of k for which 2x2 +kx+3 =0 has two equal and real root

1.	Find the value of k for which 2x2 +kx+3 =0 has two equal and real roots.
Answer» Since the eqaution has two equal roots, then b^2 - 4ac = 0== k^2 - 4×2×3=0 == k^2 - 24 == k^2=24 == k=+-√24 == k= +-2√6

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