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Find the value of k, for which one root of the quadratic equation k×2-14×+8=0 is 2

Answer» Given:\xa0Equation: kx²-14x+8= 0Also, One root of this Equation is 2Substitute the Given value in Equation!kx²-14x+8 = 0k(2)² -14(2)+8 = 0k4-28+8 = 04k-20 = 04k= 20•°• k = 20/4=> k = 5\xa0


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