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Find the value of k for which one root of the quadratic equation kx2-14x+8=0is six times the other

Answer» Le➰ and 6➰ be the roots of the quadratic equation kx2-14x + 8=0,then?➰+6➰ = - coefficient of x / coefficient of x2 = -(-14)/k?7➰=14/k?➰ = 2/k. ........1 And ➰(6➰) = constantin / coefficient of x2 = 8/k . ......2 6➰=8/kFrom 1 and 2 eq. 6{2/k} square = 8/k k= 24/8 ?k =3


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