Find the value of k for which one root of the quadratic equation kx-14

1.	Find the value of k for which one root of the quadratic equation kx-14x+8=0 is 2
Answer» K=10 kx - 14x + 8 = 0If x = 2k(2) - 14(2) + 8 = 02k - 28 + 8 = 02k - 20 = 02k = 20k = 10\xa0 Sorry, it will be K=10. My previous answer was wrong. F(x)=kx-14x+8=0 =K(2)-14(2)+8=0 =2k-28+8=0 =2k-36=0. =2k=36 =K=36÷2 K=18 Let P(x)=kx-14x+8=0=P(2)=k(2)-14(2)+8=0=2k-28+8=0=2k-20=0=2k=20=K=10 K=18.

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