Find the value of k for which the lines (k+1)x + 3ky + 15=0 and 5x +ky +5=0 are coincident

Find the value of k for which the lines (k+1)x + 3ky + 15=0 and 5x +ky

1.	Find the value of k for which the lines (k+1)x + 3ky + 15=0 and 5x +ky +5=0 are coincident
Answer» a1/a2=b1/b2=c1/c2(K+1)/5=3k/k=15/5Cross ✖ a1/a2&b1/b2We getK(k+1)=5(3k)K²+k=15kK²-14k=0K-14=0K=14Put value of kK+1/515/53.3k/k42/14=3Therefore,a1/a2=b1/b2=c1/c2