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| 1. |
Find the value of k, for which the point are collinear (8,1),(k, -4),(2,-5) |
| Answer» (8, 1), (k, -4), (2, -5)Since, the given points are collinear, it means the area of triangle formed by them is equal to zero.Area of Triangle = {tex}\\frac{1}{2}\\left[ {{x_1}({y_2} - {y_3}) + {x_2}({y_3} - {y_1}) + {x_3}({y_1} - {y_2})} \\right] = 0{/tex}⇒ ½ [8 {−4−(−5)} +k(−5−1)+2{1−(-4)}]⇒ ½ (8 − 6k + 10 )= 0⇒ ½ (18 − 6k) = 0⇒ 18 − 6k = 0⇒ 18 = 6k⇒ k = 3 | |