Find the value of k for which the points (3k-1,k-2), (k,k-7) , and (k-1,-k-2) are collinear.

Find the value of k for which the points (3k-1,k-2), (k,k-7) , and (k-

1.	Find the value of k for which the points (3k-1,k-2), (k,k-7) , and (k-1,-k-2) are collinear.
Answer» Thanks bhai Equation will be like this 4k^2 -12k+0=0 then taking 4k as common then 4k(k-3)=0 And u will get the answer as mentioned Right answer is K=0 and K = 3 2k^2-6k-5=0,meri ye equation ban rhi hai , but k ki value nhi aa rhi Answer KYa aa rha h mera to koi square = 3k aa rha h Plz solve this problem