Find the value of k for which x=2 is a solution of the equation kx2+2x

1.	Find the value of k for which x=2 is a solution of the equation kx2+2x-3=0
Answer» f(x) = kx2 + 2x - 3put x = 2f(2) = k(2)2 + 2(2)- 3= 4k +4 - 3= 4k + 1If x = 2 is solution of given equation then f(2) = 04k + 1 = 04k = -1k = -1/4\xa0

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