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Find the value of k if 2 is the solution of polynomial x square minus 2 k x + 5 |
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Answer» If x = 2x2 - 2kx + 5 = 0\xa0(2)2 - 2k(2) + 5 = 04 - 4k + 5 = 0-4k + 9 = 04k = 9k = 9/4 Put 2 as the value of x (2)^2- 2k (2) +5 ( substitution of x )4-4k+5=09-4k=0-4k=-9K= 9/4 -5/4 |
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