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Find the value of k if the points A(2,3), B(4,k) and C(6,-3) are colliner |
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Answer» When three points are collinear then the condition isx1 (y 2 - y3) + x2(y3 - y1) + x3(y1 - y2) = 0Where, x1 = 2, x2 = 4, y1 = 3, y2 = k, x3 = 6, y3 = -3Substituting the values,2(k + 3) + 4(-3 - 3) + 6(3 - k) = 02k + 6 + 4(-6) + 18 - 6k = 02k + 6 - 24 + 18 - 6k = 0-4k + 0 = 0k=0Therefore, The value of k is 0. I think the value of k will be 0. SORRY BRO... I DON\'T NO |
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