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Find the value of k .If the points A(k+1,2k) B(3k,2k+3) and C(5k-1,5k) are collinear? |
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Answer» 2 1/2(k+1(2k+3-5k) + 3k (5k - 2k) +5k-1(2k-2k-3))=0k+1(-3k +3)+3k(3k)+5k-1(-3)=0-3k²+3k-3k+3+9k²-15k+3=06k²-15k+6=0By using splitting the middle term method,6k²-12k-3k+66k(k-2)-3(k-2)(6k-3)(k-2)K=1/2 or 2 |
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