Find the value of k if x-2 is a factor of x2-kx+10

1.	Find the value of k if x-2 is a factor of x2-kx+10
Answer» X=2X²-kx+10=02²-k(2)+10=04-2k+10=0-2k+4+10=0-2k+14=0-2k=-14K=-14/-2K=7 Given x-2=0.....so, x=22²-2k+10=0-2k=-10-42k=14 (cancelling negative sign)k=14/2k=7#Hope it is helpful... Put x = 2x2-kx+10 = 0\xa0(2)2 - k(2) + 10 = 04 - 2k + 10 = 0-2x +14 = 0-2x = -14x = 14/2 = 7

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