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| 1. |
Find the value of k in given points A(2,3) B(4,K) C(6,-3)are the collinear |
| Answer» x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) = 0,....2(k + 3) + 4(-3 - 3) + 6(3 - k) = 0, .....2k + 6 + 4(-6) + 18 - 6k = 0,......2k + 6 - 24 + 18 - 6k = 0,.....-4k + 0 = 0,....-4k=0,...k=0 | |