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Find the value of \'k\' so that equations have equal roots Kx(x-2) +6=0 |
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Answer» D=b2- 4ac=0(-2k)2 -4(k)(6)=0(4k)2-4k(6)=016k2-24k=016k2=24kK=6 Kx (x-2)+6=0=> kx^2-2kx+6=0Now this equation has equal rootsTherefore D=0=>b^2-4ac=0=>(-2k)^2-4×k×6=0=>4k^2-24k=0=>4k (k-6)=0=>k=0 or k=6 |
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