Find the value of k so that the equations 3x-2y-7=0, kx+5y+8=0 have a unique solution

Find the value of k so that the equations 3x-2y-7=0, kx+5y+8=0 have a

1.	Find the value of k so that the equations 3x-2y-7=0, kx+5y+8=0 have a unique solution
Answer» Given equations are3x - 2y = 0 ...........\xa0(1),kx + 5y = 0 ..........\xa0(2)From (1){tex}\\Rightarrow{/tex}\xa03x = 2yx=\xa0{tex}\\frac{2y}{{3}}{/tex}Now we put the value of x in equation (2).\xa0k({tex}\\frac{2y}{{3}}{/tex}) + 5y = 0k({tex}\\frac{2y}{{3}}{/tex}) = - 5y2ky = -3{tex}\\times{/tex}5y2k = -15k = {tex}\\frac{-15}{{2}}{/tex}So the value of k = -7.5