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Find the value of `k` so that the following quadratic equestion has equal roots.... 2x2-(k-2)x+1=0 |
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Answer» b2-4ac=0-(k-2)^2-4×2×1(-K+2)^2-8K^2+4-4k-8K^2-4k-4=0K^2-(2+2)k-4=0K^2-2k-2k-4=0K(k-2)-2(k-2)(K-2)(k-2)K=2,k=2Hence the value of k is 2 Anushka...i use it bt the eq. i get was.. k square - 4k-4=0 The equation is. 2x2-(k-2)x+1=0 U can use the formula" b square - 4ac=0" Can you write the equation once again |
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