Saved Bookmarks
| 1. |
Find the value of k so that the following system of equation has no solution 3x-y-5k,6x-2y-k=0 |
| Answer» Given system of equations is ,3x\xa0- y - 5 = 0 and 6x - 2y -\xa0k = 0Here a1\xa0=\xa03, b1= -1, c1 = -5 and a2 = 6, b2 = -2, c2 = - kFor no solution\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } = \\frac { b _ { 1 } } { b _ { 2 } } \\neq \\frac { c _ { 1 } } { c _ { 2 } }{/tex}\xa0{tex}\\implies{/tex}\xa0{tex}\\frac{3}{6}{/tex}\xa0=\xa0{tex}\\frac{1}{2}{/tex}\xa0{tex}\\ne{/tex}\xa0{tex}\\frac{-5}{-k}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{1}{2}{/tex}\xa0{tex}\\ne{/tex}\xa0{tex}\\frac{5}{k}{/tex}{tex}\\implies{/tex}k\xa0{tex}\\ne{/tex}\xa010 | |