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find the value of k so that they have equal to 2 X square + kx + 3 equal to zero |
| Answer» 2x2 + kx +3=0We know that quadratic equation has two equal roots only when the value of discriminant is equal to zero.Comparing equation 2x 2 +kx +3=0 with general quadratic equation ax2 + bx + c =0, we get a = 2, b = k and c = 3Discriminant = b2 − 4ac = k2 - 4(2)(3) = k2 -24Putting discriminant equal to zerok2 - 24 = 0 ⇒ k2 = 24{tex}\\Rightarrow k = \\pm \\sqrt { 24 } = \\pm 2 \\sqrt { 6 } \\Rightarrow k = 2 \\sqrt { 6 } , - 2 \\sqrt { 6 }{/tex} | |