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| 1. |
find the value of k2xsq+kx+3=0 |
| Answer» Discriminant = b^2-4acWe have,B=K,A=2,C=3.put this values on there places K^2-4x2x3=0 (Put this in equal to zero)K^2-24= 0Take 8 other side of equal so it will be +24K^2= 4When we remove square from k on other side of equal root will chargeK= √24So are k will be K= 2√6 are final answer | |