InterviewSolution
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| 1. |
Find the value of `log" " tan 1^(@) log" " tan 2^(@) … log" " tan 89^(@)`. |
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Answer» `log tan 1^(@) log tan 2^(@)* * * log tan 89^(@)` `" "=log tan 1^(@) log tan 2^(@)* * * log tan 45^(@) * * * log tan 89^(@)` `" "= log tan 1^(@) log tan 2^(@) * * * (log 1) * * * log tan 89^(@)` ` " "=0 (as log 1 = 0)` |
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