Find the value of p, for which one root of quadratic equation PX2-14X+8=0is 6 times the other

Find the value of p, for which one root of quadratic equation PX2-14X+

1.	Find the value of p, for which one root of quadratic equation PX2-14X+8=0is 6 times the other
Answer» P=+-3 Given\xa0px2-14x+8=0let a and b be the roots of the equationb=6asum of roots = -b/aproduct of roots = c/ahere a=p , b=-14 , c=8a+b=14/pab=8/pa+6a=14/p7a=14/pa=2/pa6a=8/p6a2=8/p3a2=4/p3(2/p)2=4/p3*4/p2=4/pp=3