Find the value of p, for which one root of the quadratic equation px2-14x+8=0 is 6 times the other.

Find the value of p, for which one root of the quadratic equation px2-

1.	Find the value of p, for which one root of the quadratic equation px2-14x+8=0 is 6 times the other.
Answer» \\begin{array}{l}pa^2-14a+8=0\\;\\;-(1)\\\\p(6a)^2-14(6a)+8=0\\\\or\\;\\;36pa^2-84a+8=0---(2)\\\\Now\\;mutipy(1)\\;by\\;36\\;we\\;get\\\\36pa^2-504a+288=0\\;---(3)\\\\No\\;subtract\\;(3)\\;fom\\;(2)\\\\420a=280\\;\\;so\\;a=\\frac{280}{420}=\\frac23\\\\Now\\;put\\;value\\;of\\;a\\;in\\;(1)\\\\p\\times\\frac49-14\\times\\frac23+8=0\\\\4p-84+72=0\\\\4p=12\\;s\\;p=3\\\\\\end{array} No time for this