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Find the value of p if numbers x,2x+p,3x+6are three consecutive terms of an AP |
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Answer» a2-a1=a3-a2 =2x+p-x=3x+6-2x+p = p=3 d=2x+p-x=x+p_____(1) d=3x+6-(2x+p) =x+6-p _____(2)From 1st and 2ndX+p=x+6-pp+p=6P=3 Are bhai sudhanshu give me your mobile number x,2x+p,3x+6Now according to the question,•3x+6-2x-p=2x+p-x•1x+6-p=1x+p•6=2p•p=3Therefore value of p=3 Sorry yar p=3 Hey tell me how P=6 P=3 |
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