Find the value of P such that quadratic equation ( P-12)x2-2(P-12)x+2=0 has equal root

Find the value of P such that quadratic equation ( P-12)x2-2(P-12)x+2=

1.	Find the value of P such that quadratic equation ( P-12)x2-2(P-12)x+2=0 has equal root
Answer» (P -12)x² +2( P -12) x + 2 =0 have two real and equal roots so, D = b² -4ac =0here, b = 2( P -12) a = (P -12) c = 2 now, D = {2(P -12)}² -4.2(P -12) =04{ (P -12)² -2( P -12) } =0(P -12)² -2(P -12)=0(P -12){ P -12 -2} = 0(P -12)( P -14) =0P = 12, 14 hence value of P = 12,14