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Find the value of P such that the quadratic equation (p-12)x²-2(p-12)x+2=0 has equal root

Answer» Since the equation has equal rootsTherefore D=0 b^2-4ac=0 [2(p-12)]^2 -4*(p-12)(2)=0 4(p-12){(p-12)-2}=0 (p-12)(p-14)=0 p=12 or p=14


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