Find the value of Q so that the quadratic equation px (X-3)+9=0 has tw

1.	Find the value of Q so that the quadratic equation px (X-3)+9=0 has two equal roots
Answer» we have,{tex}px^2 - 3px + 9 = 0\xa0{/tex}put a = p , b = -3p, c = 9 in\xa0{tex}b^{2}-4 ac{/tex}{tex}b^2 - 4ac = (-3p)^2 - 4(p)(9){/tex}{tex}= 9p^2 - 36p{/tex}for having equal roots\xa0{tex}b^2 - 4ac = 9p^2 - 36p = 0\xa0{/tex}{tex}9p^2 - 36p = 0\xa0{/tex}9p(p - 4)\xa0= 0\xa09p = 0 or p - 4 = 0\xa0p = 0 or p = 4

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