Find the value of under root 6+ root 6 + root 6 + ...

1.	Find the value of under root 6+ root 6 + root 6 + ...
Answer» Given : x = √6 + √6 + √6 +... ---(i)Then,x = √6 + x --- From Eqn. (i)On squaring both sides,⇒ x² = 6 + x⇒ x² - x - 6 = 0⇒ x² - 3x + 2x - 6 = 0⇒ x(x-3) + 2(x-3) = 0⇒ x = 3 Or x = -2But x is a natural number.∴ x = 3\xa0\xa0 Can you write it step-by-step!By the way sis not bro.

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