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Find the value of x, if \(21^{^\sqrt x} + 20^{^\sqrt x} = 29^{^\sqrt x}\)1. 22. 33. 04. 4 |
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Answer» Correct Answer - Option 4 : 4 Given: 21√x + 20√x = 29√x Formula used: Using phythagorus theorem a2 + b2 = c2 Calculation: 21√x + 20√x = 29√x Compare the whole equation a2 + b2 = c2 So √x = 2 x = 4 212 + 202 = 292 441 + 400 = 841 841 = 841 So x = 4 satisfy this equation ∴ The value of x is 4. |
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