1.

Find the value of x, if \(21^{^\sqrt x} + 20^{^\sqrt x} = 29^{^\sqrt x}\)1. 22. 33. 04. 4

Answer» Correct Answer - Option 4 : 4

Given:

21√x + 20√x  = 29√x

Formula used:

Using phythagorus theorem

a2 + b2 = c2

Calculation:

21√x + 20√x = 29√x

Compare the whole equation a2 + b2 = c2

So √x = 2

x = 4

212 + 202 = 292

441 + 400 = 841

841 = 841

So x =  4 satisfy this equation

 ∴ The value of x is 4.



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