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Find the value of x, if \(\begin{vmatrix}2& 4 \\[0.3em]5& 1\end{vmatrix}\)= \(\begin{vmatrix}2x& 4 \\[0.3em]6& x\end{vmatrix}\) |
Answer» \(\begin{vmatrix}2& 4 \\[0.3em]5& 1\end{vmatrix}\)= \(\begin{vmatrix}2x& 4 \\[0.3em]6& x\end{vmatrix}\) ⇒ 2 × 1 – 4 × 5 = 2x × x – 4 × 6 ⇒ 2 – 20 = 2x2 – 24 ⇒ 2x2 = –18 +24 ⇒ 2x2 = 6 ⇒ x2 = 3 ⇒ x = ±√ 3 |
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