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Find the value of x, if\(\begin{vmatrix} 3& x \\[0.3em] x& 1 \end{vmatrix}\)= \(\begin{vmatrix} 3& 2 \\[0.3em] 4& 1 \end{vmatrix}\) |
Answer» \(\begin{vmatrix} 3& x \\[0.3em] x& 1 \end{vmatrix}\)= \(\begin{vmatrix} 3& 2 \\[0.3em] 4& 1 \end{vmatrix}\) ⇒ 3 × 1 – x × x = 3 × 1 – 4 × 2 ⇒ 3 – x2 = 3 – 8 ⇒ – x2 = –5 –3 ⇒ –x2 = –8 ⇒ x = ±2√ 2 |
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