1.

Find the value of x, if\(\begin{vmatrix} 3& x \\[0.3em] x& 1 \end{vmatrix}\)= \(\begin{vmatrix} 3& 2 \\[0.3em] 4& 1 \end{vmatrix}\)

Answer»

\(\begin{vmatrix} 3& x \\[0.3em] x& 1 \end{vmatrix}\)\(\begin{vmatrix} 3& 2 \\[0.3em] 4& 1 \end{vmatrix}\) 

⇒ 3 × 1 – x × x = 3 × 1 – 4 × 2 

⇒ 3 – x2 = 3 – 8 

⇒ – x2 = –5 –3 

⇒ –x2 = –8 

⇒ x = ±2√ 2



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