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| 1. |
Find the value of x if the distance between the points (x,-1) and (3,-2) is x+5 |
| Answer» We have to find the value of x, if the distance between the points (x, -1) and (3, 2) is 5.Let P(x, -1) and Q(3, 2) be the given points. Then,PQ = 5{tex}\\Rightarrow \\quad \\sqrt { ( x - 3 ) ^ { 2 } + ( - 1 - 2 ) ^ { 2 } } = 5{/tex}Squaring both sides,we get,{tex}\\Rightarrow{/tex}(x - 3)2 + 9 = 52\xa0{tex} \\Rightarrow{/tex}x2 - 6x + 18 = 25{tex}\\Rightarrow{/tex}\xa0x2 - 6 x - 7 = 0{tex}\\Rightarrow{/tex}(x - 7) (x + 1) = 0{tex}\\Rightarrow{/tex}\xa0x = 7 or, x = -1 | |