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Find the values of k for which following equation has real roots kx ( x-3) + 9 = 0 |
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Answer» This is for real and equalI want to know for real roots so it can be distinct also Given, Quadratic Equation is kx(x - 3) + 9 = 0.⇒ kx² - 3kx + 9 = 0On comparing with ax² + bx + c = 0, we get a = k, b = -3k, c = 9.Given that the equation has real equal and real roots.∴ D = 0b² - 4ac = 0⇒ (-3k)² - 4(k)(9) = 0⇒ 9k² - 36k = 0⇒ 9k² = 36k⇒ 9k = 36⇒ k = 36/9⇒\xa0k = 4 |
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